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Here are the boundary conditions for this example
(16) u(0, t) = 0
(17) u(1, t) = 0
and finally initial conditions are
(18) u(x, 0) = f(x)
(19) (x, 0) = g(x)
(20) u(0, t) = X(0)T(t) = 0
(21) u(1, t) = X(1)T(t) = 0
If X(0)T(t) = 0 then either X(0) = 0 or T(t) = 0. If T(t) = 0 then u(x, t) = 0 which is a trivial solution and it is not of interest; therefore X(0) = 0. Similarly one can conclude from X(1)T(t) = 0 that X(1) = 0.
(22) Tn(t) = ancos(nCπt) + bnsin(nCπt)
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