For each wheel, friction force is f and there are 16 wheels. Force balance on the entire aircraft leads to the following equation
(1) F − 16f = Ma
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(2) fr = Iα = I(a)/(r)⇒ f = (Ia)/(r2)⇒ F − (16Ia)/(r2) = MaThus, initial linear acceleration of the aircraft is given by(3) a = (F)/(M + (16I)/(r2))
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- Just after the touchdown, the translational velocity of the wheels is more than that of the rolling velocity. Thus the wheels slip (Vl > ωr). This phase is depicted in Figure 4.
- In the rolling phase, when the wheels are undergoing pure rolling motion, the velocity of the wheels is given by Vl = ωr. The angular velocity ω of the wheels is constant in this phase, since there is no frictional force acting to reduce it. This phase of pure rolling is depicted in Figure 5.
- When the brakes have been applied, the velocity of the wheels is still given by Vl = ωr. However the wheels undergo deceleration due to the applied torque and thus the angular velocity of the wheels (ω) is not a constant. The maximum frictional force acting is limited by the coefficient of static friction. The braking phase is depicted in Figure 6.
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